A and B can do a job in 6 days and 12 days respectively. They began the work together but A left after 3 days. In how many days was the remaining work completed by B? MCQ with Answer and Explanation
A and B can do a job in 6 days and 12 days respectively. They began the work together but A left after 3 days. In how many days was the remaining work completed by B?
A. 3 days
B. 2 days
C. 4 days
D. 5 days
Answer: Option A
Solution (By JKSSB Mock Tests)
Total work = LCM(6, 12) = 12 units. Efficiency of A = 2, B = 1. Combined efficiency = 3 units/day. In 3 days, work done = 3 * 3 = 9 units. Remaining work = 12 - 9 = 3 units. Time taken by B to complete remaining work = 3 / 1 = 3 days.
Explanation:
Let B's efficiency = 1, then A's efficiency = 3. Combined efficiency = 3 + 1 = 4. Total work = 18 * 4 = 72 units. Time taken by A alone = 72 / 3 = 24 days.
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