A and B work together. A alone can complete the work in 18 days and B alone in 26 days. What percentage of the total daily work is contributed by A? MCQ with Answer and Explanation

Explanation:
Let efficiency of B = 5, then efficiency of A = 7. Combined efficiency = 12 units/day. Total work = 10 * 12 = 120 units. Time taken by A alone = 120 / 7 = 17(1/7) days.

Explanation:
Combined rate = 1/19 + 1/19. Time = 9.5 days.

Explanation:
Total work = 12M * 4 = 48 man-days = 15W * 4 = 60 woman-days. So, 48M = 60W => 4M = 5W => 1M = 1.25W. Work done by 6 men in 2 days = 12 man-days. Remaining work = 48 - 12 = 36 man-days. Converting to woman-days: 36 * 1.25 = 45 woman-days. To complete 45 woman-days in 3 days, number of women required = 45 / 3 = 15 women.