A and B work together. A alone can complete the work in 24 days and B alone in 22 days. What percentage of the total daily work is contributed by A? MCQ with Answer and Explanation

Explanation:
Total capacity = LCM(12, 15, 20) = 60 units. Efficiency of A = 5, B = 4. Combined efficiency of A+B+C = 3. Efficiency of C = 3 - (5 + 4) = -6. Thus, C empties 6 units/minute. Time taken by C to empty the full cistern = 60 / 6 = 10 minutes.

Explanation:
Efficiency of 10 men = 1/7, so 1 man = 1/70. Efficiency of 10 women = 1/14. Efficiency of 5 men and 10 women = 5*(1/70) + 1/14 = 1/14 + 1/14 = 2/14 = 1/7. Thus, they will complete the work in 7 days.

Explanation:
Total work = LCM(10, 15, 30) = 30 units. Efficiency of A = 3, B = 2, C = 1. In a 3-day cycle (A on day 1, B on day 2, C on day 3), work completed = 3 + 2 + 1 = 6 units. Number of cycles required = 30 / 6 = 5 cycles. Total days = 5 * 3 = 15 days.