A body starts from rest and moves with uniform acceleration. Which graph accurately represents its motion? MCQ with Answer and Explanation

A body starts from rest and moves with uniform acceleration. Which graph accurately represents its motion?
A. A straight horizontal line on a velocity-time graph.
B. A parabolic displacement-time graph curving upwards.
C. A straight line displacement-time graph passing through origin.
D. A decreasing straight line on a velocity-time graph.
Answer: Option B
Solution (By JKSSB Mock Tests)
For uniform acceleration starting from rest, the displacement equation is s = ½at². Since displacement 's' is proportional to the square of time (t²), the displacement-time graph is a parabola curving upwards. A straight horizontal line on a v-t graph means constant velocity (zero acceleration).

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Practice More Physics Questions

Question #1
A sound wave has wavelength 1.7 m and speed 340 m/s. Its frequency is
A. 578 Hz
B. 200 Hz
C. 170 Hz
D. 340 Hz

Correct Answer: Option B


Explanation:
f = v/λ = 340/1.7 = 200 Hz.

This question belongs to: Science Physics
Question #2
Work done by a man in carrying a suitcase weighing 10 kg on his head while walking 5 m horizontally (g=10) is
A. 250 J
B. 0 J
C. 50 J
D. 500 J

Correct Answer: Option B


Explanation:
Force (weight) is vertical (upward to support), displacement horizontal, angle 90°, cos90°=0, work = 0. No work against gravity because vertical height doesn't change. Energy spent is internal muscular effort, but physics work zero.

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Question #3
The time period of revolution of a satellite close to Earth's surface is approximately:
A. 24 hours
B. 90 minutes
C. 84 minutes
D. 12 hours

Correct Answer: Option C


Explanation:
For low Earth orbit (r ≈ R_earth), orbital period T = 2π√(r³/GM). Using g = GM/R², T = 2π√(R/g). With R = 6.4×10⁶ m, g = 9.8 m/s², T ≈ 2×3.14×√(6.4e6/9.8) ≈ 6.28×√(653061) ≈ 6.28×808 ≈ 5076 s ≈ 84.6 minutes. Memory aid: 'Low orbit period ≈ 84 min; geostationary = 24 hours'. This standard result is frequently tested in competitive exams. Always recall that period increases with orbital radius; competitive exams often compare low orbit vs geostationary periods.

This question belongs to: Science Physics