A can do a piece of work in 12 days and B can do the same work in 18 days. They work together for 4 days and then A leaves. How many days will B take to complete the remaining work?
Explanation:
Total work = LCM(12, 18) = 36 units. Efficiency of A = 3, B = 2. Combined efficiency = 5. In 4 days, work completed = 4 * 5 = 20 units. Remaining work = 36 - 20 = 16 units. Time taken by B to complete the remaining work = 16 / 2 = 8 days.
A can do a piece of work in 14 days and B in 21 days. They begin together but 3 days before the completion of the work, A leaves. The total number of days taken to complete the work is:
Explanation:
Total work = LCM(14, 21) = 42 units. Efficiency of A = 3, B = 2. Let total days be x. A works for (x - 3) days and B works for x days. 3*(x - 3) + 2*x = 42 => 3x - 9 + 2x = 42 => 5x = 51 => x = 51/5 = 10(1/5) days.
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