A and B together can do a piece of work in 9 days. If A does thrice the work of B in a given time, how many days will A alone take to complete the total work?
Explanation:
Ratio of efficiency of A : B = 3 : 1. Combined efficiency = 3 + 1 = 4. Total work = 9 * 4 = 36 units. Time taken by A alone = 36 / 3 = 12 days.
A can do a piece of work in 20 days and B in 30 days. They work together for some time and then B leaves. If A completes the remaining work in 5 days, for how many days did they work together?
Explanation:
Total work = LCM(20, 30) = 60 units. Efficiency of A = 3, B = 2. A worked alone for 5 days: work done = 5 * 3 = 15 units. Remaining work = 60 - 15 = 45 units. This was completed by A and B together. Combined efficiency = 3 + 2 = 5 units/day. Number of days they worked together = 45 / 5 = 9 days.
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