A is twice as fast as B and B is thrice as fast as C. If C alone can complete the work in 24 days, in how many days can they together finish the work? MCQ with Answer and Explanation
A is twice as fast as B and B is thrice as fast as C. If C alone can complete the work in 24 days, in how many days can they together finish the work?
A. 4 days
B. 3 days
C. 2.4 days
D. 2.6 days
Answer: Option C
Solution (By JKSSB Mock Tests)
Let efficiency of C = 1. Then efficiency of B = 3 * 1 = 3. Efficiency of A = 2 * 3 = 6. Total work = Efficiency of C * Time of C = 1 * 24 = 24 units. Combined efficiency of A, B and C = 6 + 3 + 1 = 10. Time taken together = 24 / 10 = 2.4 days.
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