A is twice as fast as B. If B can complete a work in 12 days, in how many days can A and B together complete the work?
A. 3 days
B. 4 days
C. 8 days
D. 6 days
Answer: Option B
Solution (By JKSSB Mock Tests)
B takes 12 days, so A takes 6 days. Total work = 12 units. Efficiency of A = 2, B = 1. Combined efficiency = 3 units/day. Time taken together = 12 / 3 = 4 days.
A can do a piece of work in 15 days and B in 20 days. They began the work together but A left after 4 days. In how many days will B complete the remaining work?
Explanation:
Total work = LCM(15, 20) = 60 units. Efficiency of A = 4, B = 3. Combined efficiency = 7. In 4 days, work completed = 4 * 7 = 28 units. Remaining work = 60 - 28 = 32 units. Time taken by B to complete remaining work = 32 / 3 = 10(2/3) days.
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