A is twice as good a workman as B and together they finish a piece of work in 18 days. In how many days will A alone finish the work? MCQ with Answer and Explanation
A is twice as good a workman as B and together they finish a piece of work in 18 days. In how many days will A alone finish the work?
A. 54 days
B. 36 days
C. 27 days
D. 45 days
Answer: Option C
Solution (By JKSSB Mock Tests)
Ratio of work done by A and B = 2:1. Let B's 1-day work be x, so A's 1-day work is 2x. Together, 3x = 1/18, which means x = 1/54. A's 1-day work = 2 * (1/54) = 1/27. Thus, A alone completes it in 27 days.
A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work can they finish in a day?
Explanation:
Combined 1-day work = 1/4. A's 1-day work = 1/12. B's 1-day work = 1/4 - 1/12 = 2/12 = 1/6. Therefore, B alone can complete the work in 6 days.
No comments yet. Be the first to start the discussion!