A piece of ice floats in water with 1/10 of its volume above water. The density of ice is
A. 0.5 g/cm³
B. 0.8 g/cm³
C. 0.9 g/cm³
D. 1.0 g/cm³
Answer: Option C
Solution (By JKSSB Mock Tests)
Fraction of volume submerged = ρ_ice / ρ_water. If 1/10 above, 9/10 submerged. So ρ_ice/ρ_water = 9/10 => ρ_ice = 0.9 g/cm³. Density of ice is 0.9 g/cm³.
Explanation:
Water has exceptionally high specific heat (4200 J/kg°C) due to hydrogen bonding. Used as coolant. Iron ~450, copper ~385, aluminium ~900. High specific heat moderates climate.
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