A thief escapes at 2:00 PM at a speed of 40 km/h. The owner follows him at 3:30 PM at a speed of 50 km/h. At what time will the owner catch the thief? MCQ with Answer and Explanation
A thief escapes at 2:00 PM at a speed of 40 km/h. The owner follows him at 3:30 PM at a speed of 50 km/h. At what time will the owner catch the thief?
A. 10:30 PM
B. 10:00 PM
C. 8:30 PM
D. 9:30 PM
Answer: Option D
Solution (By JKSSB Mock Tests)
By 3:30 PM, the thief has run for 1.5 hours and covered 40 * 1.5 = 60 km. Relative speed = 50 - 40 = 10 km/h. Time taken to catch = 60 / 10 = 6 hours. Catching time = 3:30 PM + 6 hours = 9:30 PM.
Explanation:
Upstream speed = 24 / 4 = 6 km/h. Upstream Speed = Speed in still water - Current speed => 6 = Speed in still water - 2 => Speed in still water = 8 km/h.
Explanation:
When A covers 100m, B covers 85m and C covers 72m. This means in a distance where B covers 85 meters, C covers 72 meters. Therefore, B beats C by 85 - 72 = 13 meters.
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