A tuning fork of frequency 256 Hz is struck and held near a closed organ pipe. Resonance occurs when pipe length is approx (v=340 m/s) MCQ with Answer and Explanation

Question

A tuning fork of frequency 256 Hz is struck and held near a closed organ pipe. Resonance occurs when pipe length is approx (v=340 m/s)

A. 17 cm

B. 33 cm

C. 50 cm

D. 66 cm

Answer: Option B

Solution (By JKSSB Mock Tests)

For closed pipe fundamental: L = v/(4f) = 340/(4×256) ≈ 340/1024 ≈ 0.332 m = 33 cm.

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Correct Answer: Option D

Explanation:
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