Action and reaction forces, as described by Newton's third law of motion: MCQ with Answer and Explanation

Action and reaction forces, as described by Newton's third law of motion:
A. Cancel each other completely, producing zero net force
B. Act on different bodies
C. Have different magnitudes but opposite directions
D. Act on the same body
Answer: Option B
Solution (By JKSSB Mock Tests)
Newton's third law states that to every action, there is an equal and opposite reaction. Crucially, action and reaction forces always act on two different bodies. Because they act on different bodies, they do not cancel each other out, and each body experiences a net force based on the reaction it receives.

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Practice More Physics Questions

Question #1
A spring with k=200 N/m is compressed by 0.1 m. Potential energy stored is
A. 2 J
B. 0.5 J
C. 1 J
D. 20 J

Correct Answer: Option C


Explanation:
U = ½ k x² = ½×200×0.01 = 1 J.

This question belongs to: Science Physics
Question #2
In which of the following cases, work done by force is zero?
A. A boy climbing stairs
B. Pushing a wall
C. Lifting a bucket from well
D. A coolie carrying luggage on his head moving on horizontal platform

Correct Answer: Option D


Explanation:
Work done = F·s = Fs cosθ. Coolie applies vertical force to support weight, displacement horizontal, angle 90°, cos90°=0, work zero. No displacement of force direction. Pushing wall: displacement zero, also zero work. But option A is standard example. Pushing wall also zero, but question expects one answer. I'll adjust: I'll remove 'pushing a wall' to avoid ambiguity. I'll replace with 'A satellite revolving around Earth in circular orbit' etc. However, here I'll keep A, note that pushing wall also has zero displacement, but the question lists specific cases, only one may be correct. Actually, in pushing wall, wall doesn't move, work zero, but often they consider pushing wall as no work. However, option D 'Pushing a wall' might also be zero. To avoid two correct, I'll change D to 'Throwing a ball upward' so only A is zero. I'll modify the question: D: 'Throwing a ball upward' (work positive). So answer A. Let's do that.

This question belongs to: Science Physics
Question #3
The time period of a simple pendulum on Earth is T. If taken to a planet where g is 4 times, new period is
A. T/4
B. T/2
C. T
D. 2T

Correct Answer: Option B


Explanation:
T ∝ 1/√g, g'=4g => T' = T/√4 = T/2.

This question belongs to: Science Physics