C.V. Raman discovered MCQ with Answer and Explanation

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C.V. Raman discovered

A. Photoelectric effect

B. Raman effect

C. Compton effect

D. Zeeman effect

Answer: Option B

Solution (By JKSSB Mock Tests)

Raman effect: inelastic scattering of light, 1928, Nobel 1930.

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Question #1

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Two resistors in series have equivalent 6 Ω, in parallel 4/3 Ω. Individual resistors are

A. 3 Ω and 3 Ω

B. 1 Ω and 5 Ω

C. 2 Ω and 2 Ω

D. 2 Ω and 4 Ω

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Correct Answer: Option D

Explanation:
Series: R1+R2=6. Parallel: (R1×R2)/(6)=4/3 => R1R2=8. Solving: R1,R2 = 2,4.

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Question #2

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An electron and a proton are accelerated through the exact same potential difference. Which particle will acquire a greater kinetic energy?

A. The proton

B. Depends on their initial velocities

C. Both will acquire the exact same kinetic energy

D. The electron

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Correct Answer: Option C

Explanation:
The work done by the electric field on a charged particle is completely converted into kinetic energy. Work = q * V, where q is the magnitude of the charge and V is the potential difference. Since both an electron and a proton have the exact same magnitude of charge (e = 1.6 x 10^-19 C), they acquire identical kinetic energy (eV).

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