Two resistors in series have equivalent 6 Ω, in parallel 4/3 Ω. Individual resistors are MCQ with Answer and Explanation

Two resistors in series have equivalent 6 Ω, in parallel 4/3 Ω. Individual resistors are
A. 2 Ω and 4 Ω
B. 2 Ω and 2 Ω
C. 3 Ω and 3 Ω
D. 1 Ω and 5 Ω
Answer: Option A
Solution (By JKSSB Mock Tests)
Series: R1+R2=6. Parallel: (R1×R2)/(6)=4/3 => R1R2=8. Solving: R1,R2 = 2,4.

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