Due to the Earth's rotation, the acceleration due to gravity (g) is minimum at:

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The effective acceleration due to gravity at latitude lambda is g' = g - R * w^2 * cos^2(lambda), where w is angular velocity. At the equator, lambda = 0, so cos(0) = 1. This subtracts the maximum outward centrifugal acceleration (Rw^2) from g. At the poles, lambda = 90, centrifugal effect is zero. Thus, g is minimum exactly at the equator.

Due to the Earth's rotation, the acceleration due to gravity (g) is minimum at: MCQ with Answer and Explanation

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