The apparent weight of a person in an elevator moving downwards with an acceleration 'a' (where a

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The apparent weight of a person in an elevator moving downwards with an acceleration 'a' (where a < g) is:

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When an elevator moves downwards with acceleration 'a', the net downward force on the person is mg - R = ma, where R is the normal reaction (apparent weight). Solving for R gives R = m(g - a). Since g - a is less than g, the apparent weight (R) is less than the true weight (mg).

The apparent weight of a person in an elevator moving downwards with an acceleration 'a' (where a < g) is: MCQ with Answer and Explanation

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