The dimension of Planck's constant is same as that of MCQ with Answer and Explanation

The dimension of Planck's constant is same as that of
A. Linear momentum
B. Force
C. Angular momentum
D. Energy
Answer: Option C
Solution (By JKSSB Mock Tests)
Planck's constant h = E/ν, so its dimensions are [Energy]/[Frequency] = [ML²T⁻²]/[T⁻¹] = [ML²T⁻¹]. Angular momentum = mvr = M·LT⁻¹·L = [ML²T⁻¹]. Energy = [ML²T⁻²], linear momentum = [MLT⁻¹], force = [MLT⁻²]. Thus, Planck's constant and angular momentum share dimensions. This is a key dimensional match in quantum mechanics.

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Practice More Physics Questions

Question #1
The velocity of a body changes from 2 m/s to 10 m/s in 4 s. Distance covered in this time is (assuming constant acceleration)
A. 48 m
B. 32 m
C. 16 m
D. 24 m

Correct Answer: Option D


Explanation:
a = (10-2)/4 = 2 m/s². s = 2×4 + ½×2×16 = 8+16=24 m. Or average velocity 6 m/s ×4=24.

This question belongs to: Science Physics
Question #2
The force of attraction between two bodies of masses 1 kg each separated by 1 m is (G=6.67×10⁻¹¹)
A. 6.67 × 10⁻⁹ N
B. 6.67 × 10⁻⁵ N
C. 6.67 × 10⁻¹¹ N
D. 6.67 × 10⁻⁷ N

Correct Answer: Option C


Explanation:
F = G×1×1/1² = 6.67×10⁻¹¹ N.

This question belongs to: Science Physics
Question #3
Atmospheric pressure at sea level is 1.013×10⁵ Pa. Equivalent height of mercury column (density 13600 kg/m³, g=9.8) is
A. 7.6 m
B. 0.76 cm
C. 13.6 m
D. 0.76 m

Correct Answer: Option D


Explanation:
P = ρgh => h = P/(ρg) = 1.013×10⁵/(13600×9.8) ≈ 0.76 m = 76 cm.

This question belongs to: Science Physics