The marked price of a machine is Rs. 3200. Two successive discounts are offered, the first being 10%. If the final selling price is Rs. 2448, find the second discount percentage. MCQ with Answer and Explanation

The marked price of a machine is Rs. 3200. Two successive discounts are offered, the first being 10%. If the final selling price is Rs. 2448, find the second discount percentage.
A. 20%
B. 15%
C. 12%
D. 18%
Answer: Option B
Solution (By JKSSB Mock Tests)
Price after first discount = 3200 * 0.90 = 2880. Second discount amount = 2880 - 2448 = 432. Second discount percentage = (432 / 2880) * 100 = 15%.

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Practice More Profit And Loss Questions

Question #1
Successive discounts of x% and 15% are equivalent to a single discount of 32%. What is the value of x?
A. 15
B. 18
C. 22
D. 20

Correct Answer: Option D


Explanation:
Equivalent multiplier = (1 - x/100) * 0.85. 1 - 0.32 = 0.68. (1 - x/100) * 0.85 = 0.68. 1 - x/100 = 0.68 / 0.85 = 0.80. x/100 = 0.20. x = 20.

This question belongs to: Maths Profit And Loss
Question #2
A man sells an article at a loss of 10%. If the cost price is Rs. 550, what is the selling price?
A. Rs. 500
B. Rs. 485
C. Rs. 505
D. Rs. 495

Correct Answer: Option D


Explanation:
Loss = 10% of 550 = 55, SP = 550 - 55 = 495.

This question belongs to: Maths Profit And Loss
Question #3
Ravi sold an article to Mohan at a profit of 10%. Mohan sold it to Shyam at a profit of 20%. If Shyam paid Rs. 1320, find the cost price for Ravi.
A. Rs. 1100
B. Rs. 1200
C. Rs. 900
D. Rs. 1000

Correct Answer: Option D


Explanation:
Let Ravi's Cost Price = X. X * 1.10 * 1.20 = 1320. 1.32X = 1320. X = 1000.

This question belongs to: Maths Profit And Loss