The moderator used in a nuclear reactor serves to MCQ with Answer and Explanation

The moderator used in a nuclear reactor serves to
A. Cool the reactor
B. Generate neutrons
C. Absorb neutrons
D. Slow down neutrons
Answer: Option D
Solution (By JKSSB Mock Tests)
Moderator slows fast neutrons to thermal energies.

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Practice More Physics Questions

Question #1
What is the equivalent capacitance when three capacitors of 3 microfarads each are connected in series?
A. 0.33 microfarads
B. 9 microfarads
C. 3 microfarads
D. 1 microfarad

Correct Answer: Option D


Explanation:
The formula for capacitors in series is exactly the opposite of resistors. 1/C_eq = 1/C1 + 1/C2 + 1/C3. Here, all are 3 uF. So, 1/C_eq = 1/3 + 1/3 + 1/3 = 3/3 = 1. Therefore, C_eq = 1 microfarad. When identical capacitors are in series, you simply divide the capacitance by the number of capacitors (3/3 = 1).

This question belongs to: Science Physics
Question #2
The instrument used to measure the wavelength of light is:
A. Microscope
B. Spectrometer
C. Telescope
D. Interferometer

Correct Answer: Option B


Explanation:
Spectrometer measures wavelengths of light using diffraction gratings or prisms to disperse light and angular measurements. Interferometer (D) can also measure wavelength but spectrometer is the standard instrument for spectral analysis. Microscope and telescope magnify images, not measure wavelength. Memory tip: 'Spectrometer = wavelength measurement via dispersion; used in spectroscopy'. This instrument-application question tests practical physics knowledge, frequently examined in competitive exams. Always associate instruments with their primary function; competitive exams often test context-specific uses.

This question belongs to: Science Physics
Question #3
Due to the Earth's rotation, the acceleration due to gravity (g) is minimum at:
A. The Equator
B. The South Pole
C. A latitude of 45 degrees
D. The North Pole

Correct Answer: Option A


Explanation:
The effective acceleration due to gravity at latitude lambda is g' = g - R * w^2 * cos^2(lambda), where w is angular velocity. At the equator, lambda = 0, so cos(0) = 1. This subtracts the maximum outward centrifugal acceleration (Rw^2) from g. At the poles, lambda = 90, centrifugal effect is zero. Thus, g is minimum exactly at the equator.

This question belongs to: Science Physics