The power of a lens is -2 D. This lens is: MCQ with Answer and Explanation

The power of a lens is -2 D. This lens is:
A. Concave lens of focal length 200 cm
B. Convex lens of focal length 50 cm
C. Convex lens of focal length 200 cm
D. Concave lens of focal length 50 cm
Answer: Option D
Solution (By JKSSB Mock Tests)
Power P = 1/f (in meters). P = -2 D ⇒ f = 1/(-2) = -0.5 m = -50 cm. Negative focal length indicates diverging (concave) lens. Convex lenses have positive power. Option A correctly states concave lens with |f| = 50 cm. Memory tip: 'Negative power = concave lens; f(in cm) = 100/P(in D)'. This direct application of lens power definition is common in competitive exams. Always convert diopters to focal length carefully, noting sign convention: negative for diverging lenses, positive for converging.

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Practice More Physics Questions

Question #1
According to Newton's Law of Cooling, the rate of loss of heat from a body is strictly proportional to:
A. The square of the temperature of the body.
B. The fourth power of the temperature difference.
C. The absolute temperature of the surroundings.
D. The temperature difference between the body and its surroundings.

Correct Answer: Option D


Explanation:
Newton's Law of Cooling is a practical approximation stating that the rate of heat loss of a body is directly proportional to the difference in temperatures between the body and its immediate environment, provided this temperature difference is relatively small. The equation is dQ/dt = -k(T_body - T_surroundings).

This question belongs to: Science Physics
Question #2
Work moving charge on equipotential surface:
A. qV
B. Zero
C. Path dependent
D. Infinite

Correct Answer: Option B


Explanation:
Equipotential: ΔV = 0 ⇒ W = qΔV = 0. Electric field perpendicular to equipotentials. Memory aid: 'Equipotential: no work to move charge along it'. Electrostatics concept frequently tested in competitive exams.

This question belongs to: Science Physics
Question #3
A convex lens of focal length 20 cm is used as a magnifying glass. For maximum magnification, object should be placed at
A. At 2F
B. Infinity
C. Just inside the focal point
D. 20 cm

Correct Answer: Option C


Explanation:
As simple microscope, object near F (just inside) gives virtual, magnified image.

This question belongs to: Science Physics