The pressure at a point in a fluid at rest depends on: MCQ with Answer and Explanation

The pressure at a point in a fluid at rest depends on:
A. Volume of the fluid
B. Shape of the container
C. Depth below the free surface
D. Area of the surface
Answer: Option C
Solution (By JKSSB Mock Tests)
Hydrostatic pressure P = P₀ + ρgh, where h is depth below free surface, ρ fluid density, g gravity. Pressure depends only on depth, not container shape, surface area, or total volume (Pascal's paradox). This is a fundamental result in fluid statics. Memory aid: 'Pressure increases linearly with depth'. Competitive exams often test this independence from container geometry to assess deep understanding versus misconceptions. Always recall that pressure is scalar and acts equally in all directions at a point in static fluid.

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A boy throws a ball vertically upward with velocity 20 m/s. Time after which ball returns to his hands (g=10) is
A. 2 s
B. 1 s
C. 4 s
D. 8 s

Correct Answer: Option C


Explanation:
Total time = 2u/g = 40/10 = 4 s.

This question belongs to: Science Physics
Question #2
A vernier caliper has 20 divisions on vernier scale matching 19 main scale divisions. If main scale division is 1 mm, least count is:
A. 0.1 mm
B. 0.5 mm
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D. 0.05 mm

Correct Answer: Option D


Explanation:
Least count = 1 MSD - 1 VSD. 20 VSD = 19 MSD ⇒ 1 VSD = 19/20 mm = 0.95 mm. LC = 1 - 0.95 = 0.05 mm. Formula: LC = MSD/n where n = vernier divisions. Memory tip: LC = smallest measurable difference = main scale value/vernier divisions. Essential for practical physics questions in competitive exams.

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Sound resonance used in:
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Correct Answer: Option A


Explanation:
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