The ratio between the speeds of two cars is 4 : 5. If the first car covers a distance of 320 km in 4 hours, what is the speed of the second car? MCQ with Answer and Explanation

The ratio between the speeds of two cars is 4 : 5. If the first car covers a distance of 320 km in 4 hours, what is the speed of the second car?
A. 80 km/h
B. 110 km/h
C. 90 km/h
D. 100 km/h
Answer: Option D
Solution (By JKSSB Mock Tests)
Speed of first car = 320 / 4 = 80 km/h. Ratio of speeds is 4:5, so 4 parts = 80 km/h => 1 part = 20 km/h. Speed of second car = 5 parts = 5 * 20 = 100 km/h.

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Practice More Time Speed and Distance Questions

Question #1
A thief escapes at 4:00 AM at 45 km/h. The police pursue him starting at 5:00 AM at 60 km/h. At what time will the thief be apprehended?
A. 9:00 AM
B. 8:00 AM
C. 8:30 AM
D. 7:30 AM

Correct Answer: Option B


Explanation:
By 5:00 AM, the thief has traveled for 1 hour and covered 45 km. Relative speed = 60 - 45 = 15 km/h. Time taken to catch = 45 / 15 = 3 hours. Capture time = 5:00 AM + 3 hours = 8:00 AM.

This question belongs to: Maths Time Speed and Distance
Question #2
A fugitive breaks out at 3:00 PM moving at 48 km/h. The squad pursues from the same point at 4:30 PM at 64 km/h. At what time will the squad catch the fugitive?
A. 9:30 PM
B. 10:00 PM
C. 9:00 PM
D. 8:30 PM

Correct Answer: Option C


Explanation:
By 4:30 PM, the fugitive has traveled for 1.5 hours, covering 48 * 1.5 = 72 km. Relative speed = 64 - 48 = 16 km/h. Time to catch = 72 / 16 = 4.5 hours. Catching time = 4:30 PM + 4.5 hours = 9:00 PM.

This question belongs to: Maths Time Speed and Distance
Question #3
Walking at 3/5 of his normal speed, a person is 20 minutes late to his destination. What is his normal time?
A. 35 minutes
B. 40 minutes
C. 25 minutes
D. 30 minutes

Correct Answer: Option D


Explanation:
New speed = 3/5 of normal speed => New time = 5/3 of normal time. Difference = 2/3 of normal time = 20 minutes. Normal time = (20 * 3) / 2 = 30 minutes.

This question belongs to: Maths Time Speed and Distance