The speed tracking profile of an express train is exactly 25% higher than a commercial car. Both take off from terminal A together and reach terminal B, 200 km away, at the same instant. On the corridor route, the train logs a total stall of 20 minutes at checkpoints. Find the car speed. MCQ with Answer and Explanation
The speed tracking profile of an express train is exactly 25% higher than a commercial car. Both take off from terminal A together and reach terminal B, 200 km away, at the same instant. On the corridor route, the train logs a total stall of 20 minutes at checkpoints. Find the car speed.
A. 120 km/h
B. 150 km/h
C. 100 km/h
D. 140 km/h
Answer: Option A
Solution (By JKSSB Mock Tests)
Let car speed be c, then train tracking speed is 1.25c. Time difference parameter = 200/c - 200/(1.25c) = 20/60 hours = 1/3 hours. 200/c * (1 - 1/1.25) = 1/3 => 200/c * (0.25/1.25) = 1/3 => 200/c * (1/5) = 1/3 => 40/c = 1/3 => c = 120 km/h.
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