Two balls of masses m and 2m are dropped from a height h. Neglecting air resistance, which hits the ground with greater momentum? MCQ with Answer and Explanation

Explanation:
U = ½ k x² = ½×200×0.01 = 1 J.

Explanation:
Range R = u²sin(2θ)/g. sin(2θ) maximum (=1) when 2θ=90° ⇒ θ=45°. Standard result for level ground projection. Memory aid: 'Max range at 45°; max height at 90°'. Projectile motion fact frequently tested in competitive exams.

Explanation:
ω = 2π × (rpm/60) = 2π × 120/60 = 4π rad/s.