Which of the following is NOT a fundamental SI unit? MCQ with Answer and Explanation

Which of the following is NOT a fundamental SI unit?
A. Coulomb
B. Kelvin
C. Ampere
D. Candela
Answer: Option A
Solution (By JKSSB Mock Tests)
Coulomb is the SI unit of electric charge, but it is a derived unit (Ampere × second). The seven fundamental SI units are meter (length), kilogram (mass), second (time), Kelvin (temperature), Ampere (electric current), candela (luminous intensity), and mole (amount of substance). Electric current is fundamental, making Ampere fundamental, not Coulomb.

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Practice More Physics Questions

Question #1
The resolving power of a microscope is increased by:
A. Using light of longer wavelength
B. Using oil immersion
C. Decreasing the numerical aperture
D. Reducing the magnification

Correct Answer: Option B


Explanation:
Resolving power (minimum resolvable distance) d = λ/(2NA), where NA is numerical aperture. Oil immersion increases NA by matching refractive index between slide and objective, reducing light refraction and increasing light collection. Longer wavelength (A) decreases resolving power; decreasing NA (C) worsens resolution; magnification (D) doesn't affect fundamental resolution limit. Memory aid: 'Higher NA or shorter λ ⇒ better resolution'. This application question tests optical instrument knowledge, common in competitive exams. Always link resolution to wave nature of light (diffraction limit) and instrument design factors.

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Question #2
Fuse protects circuit by:
A. Storing energy
B. Limiting voltage
C. Amplifying signal
D. Melting on overcurrent

Correct Answer: Option D


Explanation:
Fuse wire melts when current exceeds rating (Joule heating I²R), breaking circuit to prevent damage. Sacrificial overcurrent protection. Memory aid: 'Fuse = thermal cutoff; rated current slightly above normal'. Safety device function frequently tested in competitive electricity sections.

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Question #3
A particle moves such that its position coordinates (x, y) are given by x = 2t and y = t^2. The equation of its trajectory is:
A. y = x^2 / 2
B. y = 2x^2
C. y = x^2 / 4
D. y = x

Correct Answer: Option C


Explanation:
The equation of trajectory represents the path of the particle in the x-y plane, eliminating the time variable 't'. Given x = 2t, we can write t = x/2. Substitute this into the y equation: y = t^2 = (x/2)^2 = x^2 / 4. This confirms the particle moves in a parabolic path.

This question belongs to: Science Physics