Explanation:
Let efficiency of B = 1, then efficiency of A = 2. Combined efficiency = 3. Total work = 14 * 3 = 42 units. Time taken by A alone = 42 / 2 = 21 days.
A and B can complete a piece of work in 20 days and 30 days respectively. If they work on alternate days starting with B, in how many days will the work be finished?
Explanation:
Total work = LCM(20, 30) = 60 units. Efficiency of A = 3, B = 2. In 2 days (B then A), work completed = 2 + 3 = 5 units. Time taken to complete 60 units = (60 / 5) * 2 = 24 days.
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