A team of 30 men is supposed to do a work in 38 days. After 25 days, 5 more men were employed and the work was finished one day earlier than the scheduled time. How many days would it have been delayed if 5 more men were not employed?
Explanation:
Scheduled time = 38 days. Work finished 1 day earlier, so it took 37 days. For the first 25 days, 30 men worked. For the remaining 37 - 25 = 12 days, 35 men worked. Remaining work = 35 * 12 = 420 man-days. If 5 extra men were not joined, 30 men would take 420 / 30 = 14 days to complete this remaining work. Total days taken without extra men = 25 + 14 = 39 days. Delay = 39 - 38 = 1 day.
A can do a piece of work in 15 days and B in 20 days. They began the work together but A left after 4 days. In how many days will B complete the remaining work?
Explanation:
Total work = LCM(15, 20) = 60 units. Efficiency of A = 4, B = 3. Combined efficiency = 7. In 4 days, work completed = 4 * 7 = 28 units. Remaining work = 60 - 28 = 32 units. Time taken by B to complete remaining work = 32 / 3 = 10(2/3) days.
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