A can finish a work in 12 days and B can do it in 15 days. After A had worked for 3 days, B also joined him to finish the remaining work. In how many days was the remaining work completed?
Explanation:
Total work = LCM(12, 15) = 60 units. Efficiency of A = 5, B = 4. In 3 days, A completed 3 * 5 = 15 units. Remaining work = 60 - 15 = 45 units. Combined efficiency of A and B = 5 + 4 = 9 units/day. Time taken for remaining work = 45 / 9 = 5 days.
Explanation:
Let efficiency of B = 1, then efficiency of A = 2. Combined efficiency = 3 units/day. Total work = 8 * 3 = 24 units. Time taken by A alone = 24 / 2 = 12 days.
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