A can complete a work in 12 days and B can complete the same work in 27 days. If they work together, in how many days will the work be completed? MCQ with Answer and Explanation
Explanation:
Ratio of efficiency of A to B = 2 : 1. Ratio of time taken by A to B = 1 : 2. Difference in time = 2 - 1 = 1 part, which corresponds to 15 days. Therefore, time taken by B = 2 * 15 = 30 days.
A can finish a work in 12 days and B can do it in 15 days. After A had worked for 3 days, B also joined him to finish the remaining work. In how many days was the remaining work completed?
Explanation:
Total work = LCM(12, 15) = 60 units. Efficiency of A = 5, B = 4. In 3 days, A completed 3 * 5 = 15 units. Remaining work = 60 - 15 = 45 units. Combined efficiency of A and B = 5 + 4 = 9 units/day. Time taken for remaining work = 45 / 9 = 5 days.
Explanation:
A's 1-day work = 1/10, B's 1-day work = 1/15. Combined 1-day work = 1/10 + 1/15 = 5/30 = 1/6. Therefore, they will complete the work together in 6 days.
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