A is twice as efficient as B, and C is thrice as efficient as B. If they working together can finish a work in 5 days, in how many days can A alone finish it?
Explanation:
Let efficiency of B = 1. Then efficiency of A = 2, and efficiency of C = 3. Combined efficiency = 1 + 2 + 3 = 6. Total work = 5 * 6 = 30 units. Time taken by A alone = 30 / 2 = 15 days.
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