A, B and C can do a piece of work in 20, 30 and 60 days respectively. If A works everyday and is assisted by B and C together on every third day, then in how many days will the work be completed?
Explanation:
Total work = LCM(20, 30, 60) = 60 units. Efficiency of A = 3, B = 2, C = 1. Day 1: A works = 3 units. Day 2: A works = 3 units. Day 3: A+B+C work = 3 + 2 + 1 = 6 units. Work done in 3 days = 3 + 3 + 6 = 12 units. Number of 3-day cycles to complete 60 units = 60 / 12 = 5 cycles. Total days = 5 * 3 = 15 days.
Explanation:
Let efficiency of B = 10, then efficiency of A = 13. Total work = Efficiency of A * Time taken by A = 13 * 23 = 299 units. Combined efficiency of A and B = 13 + 10 = 23. Time taken together = 299 / 23 = 13 days.
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