Explanation:
Let B's efficiency be 1 unit/day, so A's efficiency is 2 units/day. Combined efficiency = 3 units/day. Total work = 3 * 14 = 42 units. Time taken by A alone = 42 / 2 = 21 days.
A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work can they finish in a day?
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