A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work can they finish in a day? MCQ with Answer and Explanation
A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work can they finish in a day?
A. 2/5
B. 1/9
C. 1/4
D. 1/6
Answer: Option D
Solution (By JKSSB Mock Tests)
Time taken by A = 18 days, so B takes 9 days. Efficiency of A = 1/18, B = 1/9. Together in one day = 1/18 + 1/9 = 3/18 = 1/6.
A and B can complete a work in 12 days and 16 days respectively. Both work together for 3 days and then A leaves. How long will B take to complete the remaining work?
Explanation:
Total work = LCM(12, 16) = 48 units. Efficiency of A = 4, B = 3. Combined efficiency = 7 units/day. In 3 days, work completed = 3 * 7 = 21 units. Remaining work = 48 - 21 = 27 units. Time taken by B to complete remaining work = 27 / 3 = 9 days.
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