A can complete a work in 24 days and B can complete the same work in 19 days. If they work together, in how many days will the work be completed? MCQ with Answer and Explanation
A work could be completed in 100 days by some workers. However, due to the absence of 10 workers, it was completed in 110 days. Find the original number of workers.
Explanation:
Let the original number of workers be x. Using M1 * D1 = M2 * D2: x * 100 = (x - 10) * 110 => 100x = 110x - 1100 => 10x = 1100 => x = 110.
A, B and C can complete a piece of work in 10, 12 and 15 days respectively. They started together but A left 2 days after the start and B left 3 days before the completion of the work. How long did the work last?
Explanation:
Total work = LCM(10, 12, 15) = 60 units. Efficiency of A = 6, B = 5, C = 4. Let total days be x. A works for 2 days. B works for (x - 3) days. C works for x days. Total work = 2*6 + (x - 3)*5 + 4*x = 60 => 12 + 5x - 15 + 4x = 60 => 9x - 3 = 60 => 9x = 63 => x = 7 days.
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