A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in: MCQ with Answer and Explanation
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
A. 35 days
B. 25 days
C. 20 days
D. 30 days
Answer: Option B
Solution (By JKSSB Mock Tests)
Total work = LCM(10, 50) = 50 units. Efficiency of (A + B) = 5, efficiency of C = 1. Total efficiency of (A + B + C) = 5 + 1 = 6. Given A = B + C. So, (B + C) + B + C = 6 => 2(B + C) = 6 => B + C = 3. Since C = 1, B = 2. Time taken by B alone = 50 / 2 = 25 days.
Explanation:
Total work = LCM(4, 5, 10) = 20 units. Efficiency of A = 5, B = 4, C = 2. Combined efficiency = 5 + 4 + 2 = 11 units/day. Time taken together = 20 / 11 = 1(9/11) days.
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