A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days can A alone finish the remaining work? MCQ with Answer and Explanation
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days can A alone finish the remaining work?
A. 5(1/2) days
B. 5 days
C. 6 days
D. 8 days
Answer: Option C
Solution (By JKSSB Mock Tests)
Total work = LCM(18, 15) = 90 units. Efficiency of A = 5, B = 6. B works for 10 days: work done = 10 * 6 = 60 units. Remaining work = 90 - 60 = 30 units. Time taken by A to finish the remaining work = 30 / 5 = 6 days.
Explanation:
Wages are distributed in the ratio of their efficiencies. Ratio of time taken = 12 : 15 : 20. Ratio of efficiencies = 1/12 : 1/15 : 1/20. Multiplying by LCM (60), we get 5 : 4 : 3.
Explanation:
Total work = 12 * 12 = 144 man-days. In 6 days, 12 men complete = 12 * 6 = 72 man-days. Remaining work = 144 - 72 = 72 man-days. Remaining men = 12 - 6 = 6 men. Time taken by 6 men to complete remaining work = 72 / 6 = 12 days.
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