A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work is completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? MCQ with Answer and Explanation

A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work is completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day?
A. 80
B. 82
C. 83
D. 81
Answer: Option D
Solution (By JKSSB Mock Tests)
Remaining days = 46 - 33 = 13 days. Remaining work = 1 - 4/7 = 3/7. Using (M1 * D1 * H1) / W1 = (M2 * D2 * H2) / W2: (117 * 33 * 8) / (4/7) = (M2 * 13 * 9) / (3/7) => (117 * 33 * 8) / 4 = (M2 * 13 * 9) / 3 => 117 * 33 * 2 = M2 * 13 * 3 => 117 * 33 * 2 = 39 * M2 => M2 = (117 * 33 * 2) / 39 = 3 * 33 * 2 = 198 men. Additional men = 198 - 117 = 81.

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Practice More Time and Work Questions

Question #1
A can complete a work in 10 days and B in 19 days. If they work together, the work will be completed in:
A. 21.55
B. 11.55
C. 16.55
D. 6.55

Correct Answer: Option D


Explanation:
Combined rate = 1/10 + 1/19. Required time = 6.55 days.

This question belongs to: Maths Time and Work
Question #2
A can complete a work in 16 days and B can complete the same work in 21 days. If they work together, in how many days will the work be completed?
A. 9.08
B. 11.08
C. 13.08
D. 15.08

Correct Answer: Option A


Explanation:
Combined rate = 1/16 + 1/21. Time = 1 ÷ combined rate = 9.08 days.

This question belongs to: Maths Time and Work
Question #3
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
A. 25 days
B. 20 days
C. 35 days
D. 30 days

Correct Answer: Option A


Explanation:
Total work = LCM(10, 50) = 50 units. Efficiency of (A + B) = 5, efficiency of C = 1. Total efficiency of (A + B + C) = 5 + 1 = 6. Given A = B + C. So, (B + C) + B + C = 6 => 2(B + C) = 6 => B + C = 3. Since C = 1, B = 2. Time taken by B alone = 50 / 2 = 25 days.

This question belongs to: Maths Time and Work