A is 40% more efficient than B. If B alone can complete a work in 14 days, then in how many days can A alone complete the same work? MCQ with Answer and Explanation

Explanation:
Total work = LCM(10, 15) = 30 units. Efficiency of A = 3, B = 2. In 2 days, A and B do 2 * (3 + 2) = 10 units. Remaining work = 30 - 10 = 20 units. This is completed by B and C in 4 days, so combined efficiency of B and C = 20 / 4 = 5 units/day. Since efficiency of B = 2, efficiency of C = 5 - 2 = 3 units/day. Time taken by C alone = 30 / 3 = 10 days.

Explanation:
Total work = LCM(8, 12, 16) = 48 units. Efficiency of (A+B) = 6, (B+C) = 4, (C+A) = 3. Summing efficiencies gives 2 * (A+B+C) = 13, so efficiency of (A+B+C) = 13/2. Time taken = 48 / (13/2) = 96 / 13 = 7(5/13) days.

Explanation:
Combined time for full work multiplied by 0.75 = 8.04 days.