If 6 men and 8 boys can do a piece of work in 10 days, then 3 men and 4 boys will do the same work in:
A. 15 days
B. 20 days
C. 12 days
D. 5 days
Answer: Option B
Solution (By JKSSB Mock Tests)
The number of workers (3 men and 4 boys) is exactly half of the original group (6 men and 8 boys). Since efficiency becomes half, the time taken will double. Total time = 10 * 2 = 20 days.
Explanation:
Let efficiency of B = 4, then efficiency of A = 5. Combined efficiency = 9 units/day. Total work = 20 * 9 = 180 units. Time taken by B alone = 180 / 4 = 45 days.
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