KE increased by 100%. Momentum increase percentage: MCQ with Answer and Explanation

KE increased by 100%. Momentum increase percentage:
A. 100%
B. 200%
C. 41.4%
D. 50%
Answer: Option C
Solution (By JKSSB Mock Tests)
KE ∝ p². Double KE ⇒ p_new = √2 p_old ⇒ increase = (√2 - 1)×100% ≈ 41.4%. Memory tip: 'KE ∝ p²; %Δp ≈ ½ %ΔKE for small changes, but use exact for large'. Energy-momentum relation frequently tested in competitive exams.

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