Three pumps working 8 hours a day can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the same tank in 1 day? MCQ with Answer and Explanation

Three pumps working 8 hours a day can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the same tank in 1 day?
A. 12 hours
B. 10 hours
C. 15 hours
D. 16 hours
Answer: Option A
Solution (By JKSSB Mock Tests)
Using P1 * D1 * H1 = P2 * D2 * H2: 3 * 2 * 8 = 4 * 1 * H2 => 48 = 4 * H2 => H2 = 12 hours.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Time and Work Questions

Question #1
A can complete a work in 10 days and B can complete the same work in 20 days. If they work together, in how many days will the work be completed?
A. 10.67
B. 12.67
C. 6.67
D. 8.67

Correct Answer: Option C


Explanation:
Combined rate = 1/10 + 1/20. Time = 1 ÷ combined rate = 6.67 days.

This question belongs to: Maths Time and Work
Question #2
A can complete a work in 10 days and B in 19 days. If they work together, the work will be completed in:
A. 21.55
B. 6.55
C. 11.55
D. 16.55

Correct Answer: Option B


Explanation:
Combined rate = 1/10 + 1/19. Required time = 6.55 days.

This question belongs to: Maths Time and Work
Question #3
A, B and C can do a piece of work in 10, 12 and 15 days respectively. They began the work together but A left after 2 days and B left 3 days before the completion of the work. How long did the work last?
A. 6 days
B. 7 days
C. 8 days
D. 5 days

Correct Answer: Option B


Explanation:
Total work = LCM(10, 12, 15) = 60 units. Efficiency of A = 6, B = 5, C = 4. Let the total time be x days. A worked for 2 days. B worked for (x - 3) days. C worked for x days. Total work = 2*6 + (x - 3)*5 + x*4 = 60 => 12 + 5x - 15 + 4x = 60 => 9x - 3 = 60 => 9x = 63 => x = 7 days.

This question belongs to: Maths Time and Work