A and B work together. A alone can complete the work in 18 days and B alone in 24 days. What percentage of the total daily work is contributed by A? MCQ with Answer and Explanation

Explanation:
Total work = LCM(10, 12, 15) = 60 units. Efficiency of (A+B) = 6, (B+C) = 5, (C+A) = 4. Summing gives 2*(A+B+C) = 15 => Efficiency of (A+B+C) = 7.5. Efficiency of C = (A+B+C) - (A+B) = 7.5 - 6 = 1.5. Time taken by C alone = 60 / 1.5 = 40 days.

Explanation:
Combined time for full work multiplied by 0.75 = 6.73 days.

Explanation:
Remaining days = 46 - 33 = 13 days. Remaining work = 1 - 4/7 = 3/7. Using (M1 * D1 * H1) / W1 = (M2 * D2 * H2) / W2: (117 * 33 * 8) / (4/7) = (M2 * 13 * 9) / (3/7) => (117 * 33 * 8) / 4 = (M2 * 13 * 9) / 3 => 117 * 33 * 2 = M2 * 13 * 3 => 117 * 33 * 2 = 39 * M2 => M2 = (117 * 33 * 2) / 39 = 3 * 33 * 2 = 198 men. Additional men = 198 - 117 = 81.