A can do a piece of work in 10 days, B in 12 days and C in 15 days. They carry out the work together and get a total of Rs. 6000 as wages. Find the share of A.
Explanation:
Total work = LCM(10, 12, 15) = 60 units. Efficiency of A = 6, B = 5, C = 4. Ratio of wages is equal to ratio of efficiencies = 6 : 5 : 4. Total ratio parts = 6 + 5 + 4 = 15. Share of A = (6 / 15) * 6000 = 6 * 400 = Rs. 2400.
If 12 men and 16 boys can do a piece of work in 5 days; while 13 men and 24 boys can do it in 4 days, then the ratio of the daily work done by a man to that of a boy is:
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
Explanation:
Total work = LCM(10, 50) = 50 units. Efficiency of (A + B) = 5, efficiency of C = 1. Total efficiency of (A + B + C) = 5 + 1 = 6. Given A = B + C. So, (B + C) + B + C = 6 => 2(B + C) = 6 => B + C = 3. Since C = 1, B = 2. Time taken by B alone = 50 / 2 = 25 days.
No comments yet. Be the first to start the discussion!