A and B work together. A alone can complete the work in 30 days and B alone in 22 days. What percentage of the total daily work is contributed by A? MCQ with Answer and Explanation
A can do a piece of work in 25 days and B can finish it in 20 days. They work together for 5 days and then A leaves. In how many days will B finish the remaining work?
Explanation:
Total work = LCM(25, 20) = 100 units. Efficiency of A = 4, B = 5. Combined efficiency = 9 units/day. In 5 days, work done = 5 * 9 = 45 units. Remaining work = 100 - 45 = 55 units. Time taken by B to complete remaining work = 55 / 5 = 11 days.
X can do a piece of work in 24 days. When he had worked for 4 days, Y joined him. If complete work was finished in 14 days, Y alone can finish that work in:
Explanation:
Let total work be 24 units. Efficiency of X = 1 unit/day. X worked for all 14 days, so work done by X = 14 * 1 = 14 units. Remaining work = 24 - 14 = 10 units. This 10 units of work was done by Y. Y worked for 14 - 4 = 10 days. So Y's efficiency = 10 / 10 = 1 unit/day. Time taken by Y alone = 24 / 1 = 24 days.
No comments yet. Be the first to start the discussion!