A can do a work in 18 days and B in 24 days. They start together but A leaves 3 days before the completion of the work. Find the total number of days taken to complete the work.
Explanation:
Total work = LCM(18, 24) = 72 units. Efficiency of A = 4, B = 3. Let total days be x. A works for (x - 3) days, B works for x days. 4(x - 3) + 3x = 72 => 4x - 12 + 3x = 72 => 7x = 84 => x = 12 days.
A can do a piece of work in 24 days and B in 30 days. They work together for 6 days and then A leaves. How many days will B take to complete the remaining work?
Explanation:
Total work = LCM(24, 30) = 120 units. Efficiency of A = 5, B = 4. Combined efficiency = 9. In 6 days, work done = 6 * 9 = 54 units. Remaining work = 120 - 54 = 66 units. Time taken by B to complete the remaining work = 66 / 4 = 16.5 days.
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