Explanation:
The number of workers (3 men and 4 boys) is exactly half of the original group (6 men and 8 boys). Since efficiency becomes half, the time taken will double. Total time = 10 * 2 = 20 days.
Explanation:
Let efficiency of C = 1, then B = 2 and A = 4. Combined efficiency = 1 + 2 + 4 = 7 units/day. Total work = 4 * 7 = 28 units. Time taken by C alone = 28 / 1 = 28 days.
A and B can do a piece of work in 45 days and 40 days respectively. They began the work together, but A left after some days and B finished the remaining work in 23 days. After how many days did A leave?
Explanation:
Total work = LCM(45, 40) = 360 units. Efficiency of A = 8, B = 9. B worked alone for 23 days, so work done = 23 * 9 = 207 units. Remaining work = 360 - 207 = 153 units. This was completed by A and B together. Combined efficiency = 8 + 9 = 17. Time worked together = 153 / 17 = 9 days. Thus, A left after 9 days.
No comments yet. Be the first to start the discussion!