Explanation:
Let efficiency of C = 1. Then efficiency of B = 3 * 1 = 3. Efficiency of A = 2 * 3 = 6. Total work = Efficiency of C * Time of C = 1 * 24 = 24 units. Combined efficiency of A, B and C = 6 + 3 + 1 = 10. Time taken together = 24 / 10 = 2.4 days.
A and B together can complete a piece of work in 12 days. They worked together for 4 days and then A left. B finished the remaining work alone in 14 more days. In how many days can A alone complete the work?
Explanation:
Let combined efficiency of A and B be 1 unit/day, so total work = 12 units. In 4 days, they complete 4 units. Remaining work = 12 - 4 = 8 units. B completes 8 units in 14 days, so B's efficiency = 8 / 14 = 4/7 units/day. Efficiency of A = 1 - 4/7 = 3/7 units/day. Time taken by A alone = 12 / (3/7) = (12 * 7) / 3 = 28 days.
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