Explanation:
Let efficiency of B = 4, then efficiency of A = 5. Combined efficiency = 9 units/day. Total work = 20 * 9 = 180 units. Time taken by B alone = 180 / 4 = 45 days.
A and B can complete a work together in 15 days. They work together for 3 days, then A leaves. If B alone completes the remaining work in 16 days, in how many days can A alone complete the whole work?
Explanation:
Let the total work be 60 units. Combined efficiency of A and B = 60 / 15 = 4 units/day. In 3 days, they complete 3 * 4 = 12 units. Remaining work = 60 - 12 = 48 units. B completes 48 units in 16 days, so B's efficiency = 48 / 16 = 3 units/day. A's efficiency = 4 - 3 = 1 unit/day. Time taken by A alone = 60 / 1 = 60 days.
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