A is 50% more efficient than B. C does half of the work done by A and B together in the same time. If C alone can do the work in 30 days, then A, B and C together can do the work in: MCQ with Answer and Explanation
A is 50% more efficient than B. C does half of the work done by A and B together in the same time. If C alone can do the work in 30 days, then A, B and C together can do the work in:
A. 12 days
B. 10 days
C. 20 days
D. 15 days
Answer: Option B
Solution (By JKSSB Mock Tests)
Let efficiency of B = 2, then efficiency of A = 3. Combined efficiency of A and B = 5. Efficiency of C = 5 / 2 = 2.5. Total work = Efficiency of C * Time of C = 2.5 * 30 = 75 units. Combined efficiency of A, B and C = 3 + 2 + 2.5 = 7.5 units/day. Time taken together = 75 / 7.5 = 10 days.
If 8 men and 12 boys can finish a piece of work in 10 days, while 6 men and 8 boys can finish it in 14 days, find the time taken by 1 man alone to complete the work.
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